Room: isMember(); memberState() only needs user id

Room::memberJoinState() was only used to check if the user has joined
the room (it couldn't be used for anything else), meaning that its best
replacement is actually not memberState() but isMember() introduced
hereby. It's also better to pass user ids instead of User objects to
memberState() and isMember() since that is enough to check membership.

# Conflicts:
#	lib/room.cpp
#	lib/room.h

1 files changed, 5 insertions, 2 deletions

diff --git a/lib/room.h b/lib/room.h
index de0c7504..179295d0 100644
--- a/lib/room.h
+++ b/lib/room.h
@@ -240,13 +240,16 @@ public:
      *
      * \return Join if the user is a room member; Leave otherwise
      */
-    Q_DECL_DEPRECATED_X("Use memberState and check against the mask") //
+    Q_DECL_DEPRECATED_X("Use isMember() instead")
     Q_INVOKABLE Quotient::JoinState memberJoinState(Quotient::User* user) const;
 
     //! \brief Check the join state of a given user in this room
     //!
     //! \return the given user's state with respect to the room
-    Q_INVOKABLE Quotient::Membership memberState(User* user) const;
+    Q_INVOKABLE Quotient::Membership memberState(const QString& userId) const;
+
+    //! Check whether a user with the given id is a member of the room
+    Q_INVOKABLE bool isMember(const QString& userId) const;
 
     //! \brief Get a display name (without disambiguation) for the given member
     //!